y^2=2+0.54(40)

Solution for y^2=2+0.54(40) equation:

y^2=2+0.54(40)

We move all terms to the left:

y^2-(2+0.54(40))=0

We add all the numbers together, and all the variables

y^2-(2.544)=0

We add all the numbers together, and all the variables

y^2-2.544=0

a = 1; b = 0; c = -2.544;
Δ = b2-4ac
Δ = 02-4·1·(-2.544)
Δ = 10.176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10.176}}{2*1}=\frac{0-\sqrt{10.176}}{2}
=-\frac{\sqrt{}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10.176}}{2*1}=\frac{0+\sqrt{10.176}}{2}
=\frac{\sqrt{}}{2}
$